The textbook has the following solved exercise in chapter 6
After obtaining the 5.23% figure, I would have set it equal to Standard Error * Critical T like described in equation 6.4 of the textbook.
Since we are given n = 37, I would have expected the standard deviation to be calculated...
Hello David,
Could you please let me know which are the relevant values you plug in the equation q+1.645*se(q) to obtain the 90% confidence intrerval [0.600, 2.690]?
Many thanks.
This site uses cookies to help personalise content, tailor your experience and to keep you logged in if you register.
By continuing to use this site, you are consenting to our use of cookies.