I think N(d1) and N(d2) will be given; i.e., based on historical exams, and just thinking about the difficulty of getting N(d1) [it would need to be given, or d1 would need to "conveniently" solve to 1.65 or 2.33], I am confident the only BSM calculation will be one where N(d1) and N(d2) are given such that you need to solve at the "superficial" level of the BSM, but not get into the d1/d2 itself (although please note, you *should* be able to figure d2; it is DD. But you can't be expected to get N(d2)).
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