Thomas Obitz
Member
Hello,
I don't get the final term in the formula for z spread. If I insert the upper bound of the sum (tau / h) into the term after the sigma, I already get exp(-(r(tau)+z) tau) ) - so the final term looks completely redundant?
Regards
Thomas
I don't get the final term in the formula for z spread. If I insert the upper bound of the sum (tau / h) into the term after the sigma, I already get exp(-(r(tau)+z) tau) ) - so the final term looks completely redundant?
Regards
Thomas