troubleshooter
Active Member
I think you are right on the money in this one. I did exactly the same...Does anyone remember the following question:
11) Calculate default rate for 3rd year [(1 - year 2 default rate) * ( 1 - year 3 default rate) = (1 - 0.1051)]
Yes. I think I got this one... default intensity = Prob of Default in year 3/probaility of survival for first 2 years = cumulative default for year 3 minus the same for year 2 divided by (1 - cumulative default upto year 2)...
I am not sure if I read the question on the test incorrectly, but I think the table of probs given for the question above contained cumulative probs, no?